Calculators / Combo price calculator / Same-game combos
Prediction markets · same-game combos

Same-game combos: a range, not one fair price

Multiplying the legs works when they are unrelated. Legs from one game are not, so the true price of a same-game combo sits somewhere between a hard floor and a hard ceiling.

The floor and the ceiling

Take two legs from one game: a team wins the game (55¢) and wins the first half (52¢). Multiplied, they come to 0.55 × 0.52 = 28.6¢. But the true chance of both happening can be anywhere in a range:

floor = max(0, P₁ + P₂ − 100) · ceiling = the smaller of P₁ and P₂

Why the multiplication misleads here

Winning the first half and winning the game are strongly related. A team that leads at halftime wins far more often than a team that trails. So the true chance of both is well above 28.6%, and a quote that looks overpriced on the simple check may be fair.

Your estimate that both happenReal markup on a 36¢ quote
28.6% (no relationship)+26%
30%+20%
35%+3%
40%−10% (below fair)
45%−20% (below fair)

Which way do common pairs lean?

These are tendencies, not rules, and the market prices them in. For legs that move together, the real markup is smaller than the simple check shows. For legs that work against each other, it is larger.

A three-step check for same-game combos

  1. Find the floor, the legs multiplied, and the ceiling.
  2. Estimate where the true chance sits, given how the legs relate.
  3. Compare the quote with your estimate, not with the product.

Price the legs, then adjust

The combo calculator gives the legs multiplied. Tick "same game" and treat the markup it shows as a ceiling when legs move together.

Open the combo calculator

Questions

Why is a same-game parlay priced higher than its legs multiplied?

Because legs from the same game often move together. When they do, the true chance of all of them happening is higher than the product, and market makers price that in.

What is the most a same-game combo can be worth?

No more than its least likely leg. A combo can't happen more often than any one of its parts.

Can a same-game combo be worth less than its legs multiplied?

Yes, when the legs work against each other, such as a team winning and the opposing quarterback throwing for a lot of yards.

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